{"id":318,"date":"2019-08-02T05:20:51","date_gmt":"2019-08-02T05:20:51","guid":{"rendered":"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/?post_type=chapter&#038;p=318"},"modified":"2019-08-02T05:22:21","modified_gmt":"2019-08-02T05:22:21","slug":"probability-distribution","status":"publish","type":"chapter","link":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/chapter\/probability-distribution\/","title":{"rendered":"Probability Distribution"},"content":{"raw":"<div><span style=\"float: right\"><a href=\"https:\/\/youtu.be\/lmu7WJ0AhS8\" target=\"_blank\" rel=\"noopener\"><img src=\"http:\/\/epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/2018\/11\/download.png\" alt=\"epgp books\" width=\"75px\" height=\"75px;\" \/><\/a>\r\n<\/span><\/div>\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n<div>\r\n<p style=\"text-align: justify\"><strong>1.\u00a0\u00a0 INTRODUCTION<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">In 17th century, the theory of probability was developed. The concept of probability was first developed from throwing a dice, games, tossing coins, drawing a card from a pack. In the year 1954, Antoine Gornband took an initiation to develop the probability distribution and made this area more interesting among the statisticians. In our routine life style the term <em>probability<\/em> or <em>chance<\/em> generally used. For instance, we say probably tomorrow the climate may be very hot in temperature, probably Ms.Vasanthi may come for party today, and probably you are right. These terms of possibility and probability express the same sense. But in statistics the probability has certain unique connotation unlike in Layman\u2019s outlook.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>2.\u00a0\u00a0 DEFINITIO<\/strong><strong>N<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">Probability Distribution is distinct conditions of the principal <a href=\"https:\/\/en.wikipedia.org\/wiki\/Sample_space\">sample space,<\/a> with the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Set_(mathematics)\">set <\/a>of all possible <a href=\"https:\/\/en.wikipedia.org\/wiki\/Outcome_(probability)\">results <\/a>of the random occurrence or happenings of the event which is generally observed. The sample space with the set of <a href=\"https:\/\/en.wikipedia.org\/wiki\/Real_numbers\">real numbers\/<\/a> higher-dimensional <a href=\"https:\/\/en.wikipedia.org\/wiki\/Vector_space\">vector space <\/a>and non-numerical values are considered. For instance, the sample space of a coin flip will be either head or tail. The probability theory provides a means of getting an idea of the likelihood of occurrence of different events resulting from a random experiment in terms of quantitative measures ranging between zero and one. The probability is zero for an impossible event and one for an event which is certain to occur.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>3.<\/strong>\u00a0\u00a0\u00a0 <strong>PROBABILITY DISTRIBUTIONS<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">Probability Distributions are the record of all the values of the random variables. These variables are assumed as corresponding probabilities to create a probability distribution. Random variable doesn\u2019t mean that all the values are different type or anything which is experimental study. These random variables are well explained with a set of results along with the well distinct probabilities for the happening of each outcomes of the explorative study or any research outcome. Here, the term random refers to the fact or statistics that the outcomes happen by chance or occurrence of events.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">This can be well explained with a suitable example. For instance, the probability distribution which results in rolling of a dies in solo performance, it is discussed clearly in the below table \u2013 1.<\/span><\/p>\r\n\r\n<\/div>\r\n<div>\r\n\r\n&nbsp;\r\n\r\n<strong>Table \u2013 1: Single Fair Die<\/strong>\r\n\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-141\/\" rel=\"attachment wp-att-319\"><img class=\"aligncenter size-full wp-image-319\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83.png\" alt=\"\" width=\"530\" height=\"52\" \/><\/a>\r\n<p style=\"text-align: justify\">Mean, Variance, and Standard Deviation \u2013 To understand the probability distribution, it is very important to understand the mean, media, variance and standard deviation. From the following, it is very clearly specified that, how the population of the study can be distributed systematically.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">Here, the definitions for population mean and variance are well defined for both the used ungrouped frequency distribution.<\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-142\/\" rel=\"attachment wp-att-320\"><img class=\"aligncenter size-full wp-image-320\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84.png\" alt=\"\" width=\"743\" height=\"231\" \/><\/a>\r\n<p style=\"text-align: justify\">The above syntax can be explained by taking the population (N). This N \u2013 Population is divided by the population variance, the sample variance, which was the fair estimator for the population variance. This can be divided by n-1 for computation purpose.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">After this process, you can use algebraic formulas or any equations to understand more effectively, this equation can be equivalent to:<\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-143\/\" rel=\"attachment wp-att-321\"><img class=\"aligncenter size-full wp-image-321\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85.png\" alt=\"\" width=\"745\" height=\"163\" \/><\/a>\r\n<p style=\"text-align: justify\">To recollect, the probability are elongated term to the relative frequency distribution. So every frequency (f) and Population (N) [(f\/N)] can be replaced by Probability (p) and Population (x) [p(x)].<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">This syntax can be simplified as follows:<\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-144\/\" rel=\"attachment wp-att-322\"><img class=\"aligncenter size-full wp-image-322\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86.png\" alt=\"\" width=\"369\" height=\"27\" \/><\/a>\r\n<p style=\"text-align: justify\">To understand better, two formulas can be used for the last portion of variance in the mean square calculation.<\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-146\/\" rel=\"attachment wp-att-324\"><img class=\"aligncenter size-full wp-image-324\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88.png\" alt=\"\" width=\"316\" height=\"45\" \/><\/a>\r\n\r\n&nbsp;\r\n\r\nThe above example is worked out in the table \u2013 2\r\n\r\n&nbsp;\r\n\r\n<\/div>\r\n<div>\r\n<p style=\"text-align: justify\"><strong>Table \u2013 2: Probability Distribution<\/strong><\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-147\/\" rel=\"attachment wp-att-325\"><img class=\"aligncenter size-full wp-image-325\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89.png\" alt=\"\" width=\"530\" height=\"87\" \/><\/a>\r\n<p style=\"text-align: justify\">The mean is xp(x) = (21\/6) or 7\/2 or 3.5,<\/p>\r\n<p style=\"text-align: justify\">Variance will be computed as follows \u2013<\/p>\r\n<p style=\"text-align: justify\">=\u00a0 x p(x) \u2013 x^2 p(x)<\/p>\r\n<p style=\"text-align: justify\">=\u00a0 91\/6 <strong>\u2013<\/strong> (7\/2)^2<\/p>\r\n<p style=\"text-align: justify\">=\u00a0 15.17 \u2013 12.25<\/p>\r\n<p style=\"text-align: justify\">=\u00a0 2.92<\/p>\r\n<p style=\"text-align: justify\">The standard deviation is the square root of the variance = 1.7078<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">So, we can say that Probability Distribution (Pd) is a mathematical, arithmetical, numerical, statistical, geometrical function which can be stated in very simple way to make it very easy to provide the varies probabilities of occurrence of different possible happenings of the events in any <a href=\"https:\/\/en.wikipedia.org\/wiki\/Experiment_(probability_theory)\">experiment.<\/a><\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-148\/\" rel=\"attachment wp-att-326\"><img class=\"aligncenter size-full wp-image-326\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-90.png\" alt=\"\" width=\"295\" height=\"175\" \/><\/a>\r\n<p style=\"text-align: justify\">In more methodological terms, the probability distribution is a narrative of <a href=\"https:\/\/en.wikipedia.org\/wiki\/Randomness\">random <\/a>happenings of the events which is represented in a pictorial way to understand the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability\">probabilities <\/a>of occurrence of the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Event_(probability_theory)\">events. <\/a>The probability distribution is narrated in a bell shaped curve, with unimodal peaks at a single value. It is a Symmetrical where one side is mirror of the other which is mentioned with mean, median and mode in a bell shaped curve. (Mean=Md=Mo). The Pd is symptotic on both the left and right side of the normal bell shaped curve is asymptotic to x-axis, width is determined by quantum of amount with the variation of random variable. This is not used in all the business and it also replaced by Standardized Normal Distribution (SND) in general form.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">This is a continuous distribution. It can be derived from the binomial distribution as a limiting case where n The no. of trials is very large. x &amp; P the probability of success is close to \u00bd. The general equation is<\/span><\/p>\r\n\r\n<\/div>\r\n<div>\r\n\r\n\u00a0 f(x) = 1 e\r\n\r\n\u221a2\u043f\r\n\r\n-(x-\u03bc)2\r\n\r\n\u03c3 2\r\n\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">Where the variable x lies between -\u221e &lt; x&lt; \u221e, \u03bc &amp; \u03c3 are called the parameters of the distribution. F(x) is called pdf of the normal distribution N( \u03bc ,\u03c3 2 ).The graph of the normal distribution is called the normal curve. It is bell shaped and symmetric about its mean. The two tails of the curve extend to +\u221e &amp; -\u221e the curve is unimodal. The total area under the curve is 1.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE -<\/strong><\/p>\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">(a) A coin is tossed 3 times. Find the probability of getting 2 heads and a tail in any given order.<\/span><\/p>\r\n\r\n<\/div>\r\n<div>\r\n\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-149\/\" rel=\"attachment wp-att-327\"><img class=\"aligncenter size-full wp-image-327\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91.png\" alt=\"\" width=\"564\" height=\"397\" \/><\/a>\r\n\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>3.1.<\/strong>\u00a0<strong>Normal Random Variable\/Normal Distribution (NRC\/ND)<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">The normal random variables or distributions can be described as continuous random variables. It can be better understood by two predominant ways which is represented below -(a) Density plot \u2013 Shape : Bell<\/p>\r\n<a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-151\/\" rel=\"attachment wp-att-329\"><img class=\"aligncenter size-full wp-image-329\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-93.png\" alt=\"\" width=\"203\" height=\"168\" \/><\/a>\r\n\r\n<\/div>\r\n<div>\r\n<p style=\"text-align: justify\"><strong>3.2.<\/strong>\u00a0\u00a0\u00a0<strong>Standard Normal Distribution (SND)<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">The Normal distribution with mean zero (mean=0) and standard deviation ( <em>s<\/em> \/SD=1). It denotes N (0, 1). Normally we use <em>Z<\/em> to denote a standard normal random variable. It is very important to know that for what purpose we learn or understand the SND. To calculate the area under the normal curve either numerically or geometrically. Many statisticians have established tables to indicate the left tail area under the Standard Normal Curve (SNC) of any given number. Probability distributions are a elementary model in statistics. They are used both on a theoretical point and a practical point.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>3.3.<\/strong>\u00a0\u00a0<strong>Discrete Probability Distribution (DPD) -<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">It applicable to the scenarios where the set of possible outcomes is <a href=\"https:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete,<\/a> such as a coin toss or a roll of dice can be encoded by a discrete list of the probabilities of the outcomes, known as a <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability_mass_function\">probability mass function.<\/a><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>3.4.<\/strong>\u00a0\u00a0<strong>Continuous Probability Distribution (CPD) -<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">It applicable to the scenarios where the set of possible outcomes can take on values in a continuous range (e.g., real numbers), such as the temperature on a given day) is typically described by <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability_density_function\">probability density functions <\/a>(with the probability of any individual outcome actually being 0). The <a href=\"https:\/\/en.wikipedia.org\/wiki\/Normal_distribution\">normal distribution <\/a>is a commonly encountered continuous probability distribution.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Random variable<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Random variable is a variable whose value is determined by the outcome of a random experiment. Random variable whose value is determined by the outcome of a random experiment is called a random variable. An example of this is the income of a randomly selected family. A random variable X is said to have the normal distribution with parameters \u00b5 and \u03c3 if its density function is given by: f(x) = 1 \u221a 2\u03c0 \u03c3 exp (\u2212 1 2 x \u2212 \u00b5 \u03c3 2) (6) for \u2212\u221e &lt; x &lt; \u221e. It can be shown that E(X) = \u00b5 and V (X) = \u03c3 2. Thus, the normal distribution is characterized by a mean \u00b5 and a standard deviation \u03c3.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.1.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Discrete Random Variable<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A discrete random variable is one whose set of assumed values is countable (arises from counting). Discrete random variable whose values are\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">countable is called a discrete random variable. An example of this is the number of cars in a parking lot at any particular time.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.2.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Continuous Random Variable<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A continuous random variable is one whose set of assumed values is uncountable (arises from measurement.).Continuous random variable that can assume any value in one or more intervals is called a continuous random variable. An example of this is the time taken by a person to travel by car from New York City to Boston.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">5.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">BINOMIAL DISTRIBUTION<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">In probability theory and <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistics\">statistics, <\/a><span style=\"text-align: initial;font-size: 1em\">the <\/span><strong style=\"text-align: initial;font-size: 1em\">binomial distribution<\/strong><span style=\"text-align: initial;font-size: 1em\"> is the <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete<\/a> <a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">probability distribution <\/a><span style=\"text-align: initial;font-size: 1em\">of the number of successes in a sequence of <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em> <a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistical_independence\">independent<\/a><span style=\"text-align: initial;font-size: 1em\"> yes\/no experiments, each of which yields success with <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Probability\">probability <\/a><em style=\"text-align: initial;font-size: 1em\">p<\/em><span style=\"text-align: initial;font-size: 1em\">. Such a success\/failure experiment is also called a Bernoulli experiment or <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Bernoulli_trial\">Bernoulli trial. <\/a><span style=\"text-align: initial;font-size: 1em\">In fact, when <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em><span style=\"text-align: initial;font-size: 1em\"> = 1, the binomial distribution <\/span><em style=\"text-align: initial;font-size: 1em\">is<\/em><span style=\"text-align: initial;font-size: 1em\"> a Bernoulli distribution. The binomial distribution is the basis for the popular <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Binomial_test\">binomial test <\/a><span style=\"text-align: initial;font-size: 1em\">of <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistical_significance\">statistical significance.<\/a><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE -<\/strong><\/p>\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">An elementary example is this: roll a die ten times and count the number of 1s a outcome. Then this random number follows a binomial distribution with n = 10 and p =1\/6.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">For example, assume 5% of the population is green-eyed. You pick 500 people randomly. The number of green-eyed people you pick is a <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Random_variable\">random variable <\/a><em style=\"text-align: initial;font-size: 1em\">X<\/em><span style=\"text-align: initial;font-size: 1em\"> which follows a binomial distribution with <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em><span style=\"text-align: initial;font-size: 1em\"> = 500 and <\/span><em style=\"text-align: initial;font-size: 1em\">p<\/em><span style=\"text-align: initial;font-size: 1em\"> = 0.05.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">6.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">CONDITIONAL PROBABILITY<\/strong><\/p>\r\n\r\n<\/div>\r\n<div>\r\n<p style=\"text-align: justify\">The conditional probability of two events A and B is P (A|B) =<em>P<\/em>(<em> A\u00a0\u00a0 and P<\/em>(<em>B<\/em>)\u00a0<em>B<\/em>)<\/p>\r\n<p style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">where P (A and B) means the probability of the outcomes that events A and B have in common.<\/span><\/p>\r\n\r\n<\/div>\r\n<div>\r\n\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>(i)\u00a0\u00a0<\/strong><strong>EXAMPLE \u2013<\/strong><\/p>\r\n<p style=\"text-align: justify\">When a die is rolled once, find the probability of getting a 4 given that an even number occurred in an earlier throw.<\/p>\r\n&nbsp;\r\n\r\n<strong>Solution:<\/strong>\r\n\r\n&nbsp;\r\n<p style=\"text-align: justify\">P (4 and an even number) = 1\/6<\/p>\r\n<p style=\"text-align: justify\">.i.e. P (A and B) =1\/6.<\/p>\r\n<p style=\"text-align: justify\">P (even number) =3\/6 =1\/2.<\/p>\r\n<p style=\"text-align: justify\"><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-152\/\" rel=\"attachment wp-att-330\"><img class=\"aligncenter size-full wp-image-330\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-94.png\" alt=\"\" width=\"272\" height=\"71\" \/><\/a><strong style=\"text-align: initial;font-size: 1em\">\u00a0 \u00a0(ii)\u00a0\u00a0\u00a0\u00a0\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE -<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A bag contains 3 orange, 3 yellow and 2 white marbles. Three marbles are selected without replacement. Find the probability of selecting two yellow and a white marble.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P( 1st Y) =3\/8, P( 2nd Y) = 2\/7 and P( W)= 2\/6<\/span><\/p>\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P(Y and Y and W) =P(Y) x P(Y) x P (W) = 3\/8 x 2\/7 x 2\/6 = 1 \/ 28<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(iii)\u00a0\u00a0\u00a0\u00a0<\/strong><span style=\"text-align: initial;font-size: 1em\">In a class, there are 8 girls and 6 boys. If three students are selected at random for debating, find the probability that all girls.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (G) =8\/14 and P (B) =6\/14. P (1st G) =8\/14, P (2nd G) 7\/13 and P (3rdG) = 6\/12. P (three girls) 8\/14 x 7\/13 x 6\/12= 2\/13<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(iv)<\/strong><span style=\"text-align: initial;font-size: 1em\">In how many ways can 3 drama officials be selected from 8 members?<\/span><\/p>\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">8<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">3 <\/strong><span style=\"text-align: initial;font-size: 1em\">= 56 ways.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(v)\u00a0\u00a0<\/strong><span style=\"text-align: initial;font-size: 1em\">A box has 12 bulbs, of which 3 are defective. If 4 bulbs are sold, find the probability that exactly one will be defective.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (defective bulb) = <\/span><strong style=\"text-align: initial;font-size: 1em\">3<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">1<\/strong><span style=\"text-align: initial;font-size: 1em\"> and P (non-defective bulbs) = <\/span><strong style=\"text-align: initial;font-size: 1em\">9<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">3<\/strong><\/p>\r\n<strong>3<\/strong><strong>C<\/strong><strong>1 <\/strong>x<strong>9<\/strong><strong>C<\/strong><strong>3 <\/strong>=\u00a03!<em>x\u00a09!= 252<\/em>\r\n\r\n(3 -1)!1!\u00a0(9 - 3)!3!\r\n\r\n<span style=\"text-align: initial;font-size: 1em\">P (4 bulbs from 12) = <\/span><strong style=\"text-align: initial;font-size: 1em\">12<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">4<\/strong><span style=\"text-align: initial;font-size: 1em\"> = 495.<\/span>\r\n\r\n<span style=\"text-align: initial;font-size: 1em\">P (1 defective bulb and 3 okay bulbs) = 295\/495=0.509.<\/span>\r\n\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">7.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">POISSON DISTRIBUTION<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Poisson distribution: is a <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete probability distribution <\/a><span style=\"text-align: initial;font-size: 1em\">that expresses the probability of a number of events occurring in a fixed period of time if these events occur with a known average rate, and are independent of the time since the last event. The Poisson distribution arises in many situations. It is safe to say that it is one of the three most important discrete probability distributions (the other two being the uniform and the binomial distributions). The Poisson distribution can be viewed as arising from the binomial distribution or from the exponential density.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">If the parameters n &amp; p of a binomial distribution are known then we can find the distribution. But when n is large and p is very small the application of binomial distribution is very difficult. Let x be any discrete random variable which can take values 0,1,2,3\u2026.. such that the probability distribution function of x<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P(x)=e -\u03bb \u03bbx\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">x!<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">where \u03bb is a positive constant, np = \u03bb . This distribution is called the poisson distribution.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">\u00a0Number of printing mistakes on each page of a book published by a good publisher<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of telephone calls arriving at a telephone switch board per minute<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">The Poisson distribution is a common distribution used to model \u201ccount\u201d data:<\/span><\/p>\r\n\r\n<ul>\r\n \t<li style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of telephone calls received per hour<\/span><\/li>\r\n \t<li style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of claims received per day by an insurance company<\/span><\/li>\r\n \t<li style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">Number of accidents per month at an intersection<\/span><\/li>\r\n<\/ul>\r\n<\/div>\r\n<div>\r\n<p style=\"text-align: justify\"><strong>8.\u00a0\u00a0<\/strong><strong>OBJECTIVES OF PROBABILITY DISTRIBUTION <\/strong>The core objectives of tabulation are mentioned below:<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">(a)To compute and interpret the expected value, variance, and standard deviation for a discrete random variable and work with probabilities involving a binomial probability distribution.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">(b)To work out the probabilities involving a Poisson probability distribution,<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">(c)Understand the concepts of a random variable and a probability distribution.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">(d) To decide the binomial distribution problems to be approximated by the Poisson distribution , to use the Poisson distribution in analyzing statistical<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">(e)To use the hyper geometric distribution and know how to work such problems.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>9. RULES OF PROBABILITY<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>(a)\u00a0\u00a0 <\/strong><strong>ADDITION RULES I. Rule - 1:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">When two events A and B are mutually exclusive, then P (A or B) =P (A) +P (B)<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>Example -<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">When a is tossed, find the probability of getting a 3 or 5.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">Solution: P (3) =1\/6 and P (5) =1\/6.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">Therefore P (3 or 5) = P (3) + P (5) = 1\/6+1\/6 =2\/6=1\/3.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>II. Rule \u2013 2:<\/strong><\/p>\r\n<p style=\"text-align: justify\">If A and B are two events that are NOT mutually exclusive, then P (A or B) = P (A)<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">+\u00a0\u00a0 P (B) \u2013 P (A and B), where A and B means the number of outcomes that event A and B have in common.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>Example \u2013<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">When a card is drawn from a pack of 52 cards, find the probability that the card is a 10 or a heart.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong>Solution:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">P (10) = 4\/52 and P (heart) =13\/52<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">P (10 that is Heart) = 1\/52<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\">P (A or B) = P (A) +P (B) \u2013 P (A and B) = 4\/52 _ 13\/52 \u2013 1\/52 = 16\/52.<\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(b) MULTIPLICATION RULES<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">I.\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">Rule \u2013 1: <\/strong><span style=\"text-align: initial;font-size: 1em\">For two independent events A and B, then P (A and B) = P (A) x P (B).<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Determine the probability of obtaining a 5 on a die and a tail on a coin in one throw.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution: <\/strong><span style=\"text-align: initial;font-size: 1em\">P (5) =1\/6 and P (T) =1\/2.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (5 and T) = P (5) x P (T) = 1\/6 x \u00bd= 1\/12.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">II.\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">Rule \u2013 2:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">When to events are dependent, the probability of both events occurring is P(A and\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">B)=P(A) x P(B|A), where P(B|A) is the probability that event B occurs given that\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">event A has already occurred.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><span style=\"text-align: initial;font-size: 1em\">Find\u00a0 the\u00a0 probability\u00a0 of\u00a0 obtaining\u00a0 two\u00a0 Aces\u00a0 from\u00a0 a\u00a0 pack\u00a0 of\u00a0 52\u00a0 cards\u00a0 without\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">replacement.<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P( Ace) =2\/52 and P( second Ace if NO replacement) = 3\/51<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Therefore P (Ace and Ace) = P(Ace) x P( Second Ace) = 4\/52 x 3\/51 = 1\/221<\/span><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">10. MERITS OF PROBABILITY DISTRIBUTION<\/strong><\/p>\r\n&nbsp;\r\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Merits of probability distribution and benefits of theoretical or probability distribution<\/span><\/p>\r\n\r\n<ul>\r\n \t<li><span style=\"text-align: initial;font-size: 1em\">Where the calculation of observed distribution is not possible.<\/span><\/li>\r\n \t<li>Sometime observed base distribution's calculation is not possible due to impossibility at that place we can calculate probability distribution.<\/li>\r\n \t<li>Helpful in forecasting \u2013 Probability distribution isvery helpful for forecasting and on this basis we can estimate our future and make good plans for our business.<\/li>\r\n \t<li>Helpful in Comparison \u2013 It can compare it with observed or real distribution and evaluate our efficiency of work.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<ol start=\"11\">\r\n \t<li><strong>LIMITATIONS OF PROBABILITY DISTRIBUTION<\/strong><\/li>\r\n<\/ol>\r\n<ul>\r\n \t<li style=\"text-align: justify\">Probability distribution cannot be correlated<\/li>\r\n \t<li style=\"text-align: justify\">Probability distribution cannot be viewed in chart form or in any statistical view<\/li>\r\n \t<li style=\"text-align: justify\">The data cannot be extract data from probability distribution or it cannot include in the reports<\/li>\r\n \t<li style=\"text-align: justify\">It is excluded from sensitivity analyses or charts.<\/li>\r\n \t<li style=\"text-align: justify\">Probability distribution doesn\u2019t support the Latin Hypercube sampling<\/li>\r\n<\/ul>\r\n<ol style=\"text-align: justify\" start=\"12\">\r\n \t<li><strong>CONCLUSION<\/strong><\/li>\r\n<\/ol>\r\n<p style=\"text-align: justify\">To summaries, the probability has become one of the basic tools of statistics. Sometimes statistical analysis becomes paralyzed without the theorem of probability. Probability of a given event is defined as the expected frequency of occurrence of the event among events of a like sort. According to basic economic theory, people wish to maximize their expected utility. In order to do so they should integrate the likelihood (i.e. probability) and the possible outcomes (good or bad). This means that people maximize their utility based on their perceived importance of probabilities and outcomes.<\/p>\r\n&nbsp;\r\n<table>\r\n<tbody>\r\n<tr>\r\n<td><span style=\"font-size: 16px\">you can view video on Probability Distribution <\/span><\/td>\r\n<td><a style=\"font-size: 16px\" href=\"https:\/\/youtu.be\/lmu7WJ0AhS8\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #333333\"><img class=\"alignnone wp-image-120\" src=\"http:\/\/epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/2018\/11\/download.png\" alt=\"\" width=\"36\" height=\"36\" \/><\/span><\/a><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<strong><em>Web links<\/em><\/strong>\r\n<ul>\r\n \t<li style=\"text-align: justify\">https:\/\/www.merriam-webster.com\/dictionary\/probability<\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/whatis.techtarget.com\/definition\/probability<\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda361.htm<\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/study.com\/academy\/lesson\/probability-distribution-definition-formula-example.html<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/onlinecourses.science.psu.edu\/stat200\/node\/34<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/www.thoughtco.com\/probability-distribution-3126569<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/people.richland.edu\/james\/lecture\/m170\/ch06-prb.html<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/www.utdallas.edu\/~scniu\/OPRE-6301\/documents\/Important_Probability_Distributions.pdf<\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/www.ce.memphis.edu\/7012\/pdf%20files\/Discrete_notes.pdf<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/cran.r-project.org\/web\/packages\/IPSUR\/vignettes\/IPSUR.pdf<\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda3661.htm<\/li>\r\n \t<li style=\"text-align: justify\"><a href=\"https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php\">https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php<\/a><\/li>\r\n \t<li style=\"text-align: justify\">http:\/\/study.com\/academy\/lesson\/probability-distribution-definition-formula-example.html http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda36.htm<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/www.slideshare.net\/bijayabnanda\/ls-bs-9probability-concept-and-probability-distribution<\/li>\r\n \t<li style=\"text-align: justify\">https:\/\/www.wyzant.com\/resources\/lessons\/math\/statistics_and_probability\/probability_dis tributions<\/li>\r\n<\/ul>","rendered":"<div><span style=\"float: right\"><a href=\"https:\/\/youtu.be\/lmu7WJ0AhS8\" target=\"_blank\" rel=\"noopener\"><img decoding=\"async\" src=\"http:\/\/epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/2018\/11\/download.png\" alt=\"epgp books\" width=\"75px\" height=\"75px;\" \/><\/a><br \/>\n<\/span><\/div>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<div>\n<p style=\"text-align: justify\"><strong>1.\u00a0\u00a0 INTRODUCTION<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">In 17th century, the theory of probability was developed. The concept of probability was first developed from throwing a dice, games, tossing coins, drawing a card from a pack. In the year 1954, Antoine Gornband took an initiation to develop the probability distribution and made this area more interesting among the statisticians. In our routine life style the term <em>probability<\/em> or <em>chance<\/em> generally used. For instance, we say probably tomorrow the climate may be very hot in temperature, probably Ms.Vasanthi may come for party today, and probably you are right. These terms of possibility and probability express the same sense. But in statistics the probability has certain unique connotation unlike in Layman\u2019s outlook.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>2.\u00a0\u00a0 DEFINITIO<\/strong><strong>N<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">Probability Distribution is distinct conditions of the principal <a href=\"https:\/\/en.wikipedia.org\/wiki\/Sample_space\">sample space,<\/a> with the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Set_(mathematics)\">set <\/a>of all possible <a href=\"https:\/\/en.wikipedia.org\/wiki\/Outcome_(probability)\">results <\/a>of the random occurrence or happenings of the event which is generally observed. The sample space with the set of <a href=\"https:\/\/en.wikipedia.org\/wiki\/Real_numbers\">real numbers\/<\/a> higher-dimensional <a href=\"https:\/\/en.wikipedia.org\/wiki\/Vector_space\">vector space <\/a>and non-numerical values are considered. For instance, the sample space of a coin flip will be either head or tail. The probability theory provides a means of getting an idea of the likelihood of occurrence of different events resulting from a random experiment in terms of quantitative measures ranging between zero and one. The probability is zero for an impossible event and one for an event which is certain to occur.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>3.<\/strong>\u00a0\u00a0\u00a0 <strong>PROBABILITY DISTRIBUTIONS<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">Probability Distributions are the record of all the values of the random variables. These variables are assumed as corresponding probabilities to create a probability distribution. Random variable doesn\u2019t mean that all the values are different type or anything which is experimental study. These random variables are well explained with a set of results along with the well distinct probabilities for the happening of each outcomes of the explorative study or any research outcome. Here, the term random refers to the fact or statistics that the outcomes happen by chance or occurrence of events.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">This can be well explained with a suitable example. For instance, the probability distribution which results in rolling of a dies in solo performance, it is discussed clearly in the below table \u2013 1.<\/span><\/p>\n<\/div>\n<div>\n<p>&nbsp;<\/p>\n<p><strong>Table \u2013 1: Single Fair Die<\/strong><\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-141\/\" rel=\"attachment wp-att-319\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-319\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83.png\" alt=\"\" width=\"530\" height=\"52\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83.png 530w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83-300x29.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83-65x6.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83-225x22.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-83-350x34.png 350w\" sizes=\"auto, (max-width: 530px) 100vw, 530px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">Mean, Variance, and Standard Deviation \u2013 To understand the probability distribution, it is very important to understand the mean, media, variance and standard deviation. From the following, it is very clearly specified that, how the population of the study can be distributed systematically.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">Here, the definitions for population mean and variance are well defined for both the used ungrouped frequency distribution.<\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-142\/\" rel=\"attachment wp-att-320\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-320\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84.png\" alt=\"\" width=\"743\" height=\"231\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84.png 743w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84-300x93.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84-65x20.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84-225x70.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-84-350x109.png 350w\" sizes=\"auto, (max-width: 743px) 100vw, 743px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">The above syntax can be explained by taking the population (N). This N \u2013 Population is divided by the population variance, the sample variance, which was the fair estimator for the population variance. This can be divided by n-1 for computation purpose.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">After this process, you can use algebraic formulas or any equations to understand more effectively, this equation can be equivalent to:<\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-143\/\" rel=\"attachment wp-att-321\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-321\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85.png\" alt=\"\" width=\"745\" height=\"163\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85.png 745w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85-300x66.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85-65x14.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85-225x49.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-85-350x77.png 350w\" sizes=\"auto, (max-width: 745px) 100vw, 745px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">To recollect, the probability are elongated term to the relative frequency distribution. So every frequency (f) and Population (N) [(f\/N)] can be replaced by Probability (p) and Population (x) [p(x)].<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">This syntax can be simplified as follows:<\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-144\/\" rel=\"attachment wp-att-322\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-322\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86.png\" alt=\"\" width=\"369\" height=\"27\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86.png 369w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86-300x22.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86-65x5.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86-225x16.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-86-350x26.png 350w\" sizes=\"auto, (max-width: 369px) 100vw, 369px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">To understand better, two formulas can be used for the last portion of variance in the mean square calculation.<\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-146\/\" rel=\"attachment wp-att-324\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-324\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88.png\" alt=\"\" width=\"316\" height=\"45\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88.png 316w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88-300x43.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88-65x9.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-88-225x32.png 225w\" sizes=\"auto, (max-width: 316px) 100vw, 316px\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p>The above example is worked out in the table \u2013 2<\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<div>\n<p style=\"text-align: justify\"><strong>Table \u2013 2: Probability Distribution<\/strong><\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-147\/\" rel=\"attachment wp-att-325\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-325\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89.png\" alt=\"\" width=\"530\" height=\"87\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89.png 530w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89-300x49.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89-65x11.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89-225x37.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-89-350x57.png 350w\" sizes=\"auto, (max-width: 530px) 100vw, 530px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">The mean is xp(x) = (21\/6) or 7\/2 or 3.5,<\/p>\n<p style=\"text-align: justify\">Variance will be computed as follows \u2013<\/p>\n<p style=\"text-align: justify\">=\u00a0 x p(x) \u2013 x^2 p(x)<\/p>\n<p style=\"text-align: justify\">=\u00a0 91\/6 <strong>\u2013<\/strong> (7\/2)^2<\/p>\n<p style=\"text-align: justify\">=\u00a0 15.17 \u2013 12.25<\/p>\n<p style=\"text-align: justify\">=\u00a0 2.92<\/p>\n<p style=\"text-align: justify\">The standard deviation is the square root of the variance = 1.7078<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">So, we can say that Probability Distribution (Pd) is a mathematical, arithmetical, numerical, statistical, geometrical function which can be stated in very simple way to make it very easy to provide the varies probabilities of occurrence of different possible happenings of the events in any <a href=\"https:\/\/en.wikipedia.org\/wiki\/Experiment_(probability_theory)\">experiment.<\/a><\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-148\/\" rel=\"attachment wp-att-326\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-326\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-90.png\" alt=\"\" width=\"295\" height=\"175\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-90.png 295w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-90-65x39.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-90-225x133.png 225w\" sizes=\"auto, (max-width: 295px) 100vw, 295px\" \/><\/a><\/p>\n<p style=\"text-align: justify\">In more methodological terms, the probability distribution is a narrative of <a href=\"https:\/\/en.wikipedia.org\/wiki\/Randomness\">random <\/a>happenings of the events which is represented in a pictorial way to understand the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability\">probabilities <\/a>of occurrence of the <a href=\"https:\/\/en.wikipedia.org\/wiki\/Event_(probability_theory)\">events. <\/a>The probability distribution is narrated in a bell shaped curve, with unimodal peaks at a single value. It is a Symmetrical where one side is mirror of the other which is mentioned with mean, median and mode in a bell shaped curve. (Mean=Md=Mo). The Pd is symptotic on both the left and right side of the normal bell shaped curve is asymptotic to x-axis, width is determined by quantum of amount with the variation of random variable. This is not used in all the business and it also replaced by Standardized Normal Distribution (SND) in general form.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">This is a continuous distribution. It can be derived from the binomial distribution as a limiting case where n The no. of trials is very large. x &amp; P the probability of success is close to \u00bd. The general equation is<\/span><\/p>\n<\/div>\n<div>\n<p>\u00a0 f(x) = 1 e<\/p>\n<p>\u221a2\u043f<\/p>\n<p>-(x-\u03bc)2<\/p>\n<p>\u03c3 2<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">Where the variable x lies between -\u221e &lt; x&lt; \u221e, \u03bc &amp; \u03c3 are called the parameters of the distribution. F(x) is called pdf of the normal distribution N( \u03bc ,\u03c3 2 ).The graph of the normal distribution is called the normal curve. It is bell shaped and symmetric about its mean. The two tails of the curve extend to +\u221e &amp; -\u221e the curve is unimodal. The total area under the curve is 1.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE &#8211;<\/strong><\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">(a) A coin is tossed 3 times. Find the probability of getting 2 heads and a tail in any given order.<\/span><\/p>\n<\/div>\n<div>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-149\/\" rel=\"attachment wp-att-327\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-327\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91.png\" alt=\"\" width=\"564\" height=\"397\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91.png 564w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91-300x211.png 300w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91-65x46.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91-225x158.png 225w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-91-350x246.png 350w\" sizes=\"auto, (max-width: 564px) 100vw, 564px\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>3.1.<\/strong>\u00a0<strong>Normal Random Variable\/Normal Distribution (NRC\/ND)<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">The normal random variables or distributions can be described as continuous random variables. It can be better understood by two predominant ways which is represented below -(a) Density plot \u2013 Shape : Bell<\/p>\n<p><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-151\/\" rel=\"attachment wp-att-329\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-329\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-93.png\" alt=\"\" width=\"203\" height=\"168\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-93.png 203w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-93-65x54.png 65w\" sizes=\"auto, (max-width: 203px) 100vw, 203px\" \/><\/a><\/p>\n<\/div>\n<div>\n<p style=\"text-align: justify\"><strong>3.2.<\/strong>\u00a0\u00a0\u00a0<strong>Standard Normal Distribution (SND)<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">The Normal distribution with mean zero (mean=0) and standard deviation ( <em>s<\/em> \/SD=1). It denotes N (0, 1). Normally we use <em>Z<\/em> to denote a standard normal random variable. It is very important to know that for what purpose we learn or understand the SND. To calculate the area under the normal curve either numerically or geometrically. Many statisticians have established tables to indicate the left tail area under the Standard Normal Curve (SNC) of any given number. Probability distributions are a elementary model in statistics. They are used both on a theoretical point and a practical point.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>3.3.<\/strong>\u00a0\u00a0<strong>Discrete Probability Distribution (DPD) &#8211;<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">It applicable to the scenarios where the set of possible outcomes is <a href=\"https:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete,<\/a> such as a coin toss or a roll of dice can be encoded by a discrete list of the probabilities of the outcomes, known as a <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability_mass_function\">probability mass function.<\/a><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>3.4.<\/strong>\u00a0\u00a0<strong>Continuous Probability Distribution (CPD) &#8211;<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">It applicable to the scenarios where the set of possible outcomes can take on values in a continuous range (e.g., real numbers), such as the temperature on a given day) is typically described by <a href=\"https:\/\/en.wikipedia.org\/wiki\/Probability_density_function\">probability density functions <\/a>(with the probability of any individual outcome actually being 0). The <a href=\"https:\/\/en.wikipedia.org\/wiki\/Normal_distribution\">normal distribution <\/a>is a commonly encountered continuous probability distribution.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Random variable<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Random variable is a variable whose value is determined by the outcome of a random experiment. Random variable whose value is determined by the outcome of a random experiment is called a random variable. An example of this is the income of a randomly selected family. A random variable X is said to have the normal distribution with parameters \u00b5 and \u03c3 if its density function is given by: f(x) = 1 \u221a 2\u03c0 \u03c3 exp (\u2212 1 2 x \u2212 \u00b5 \u03c3 2) (6) for \u2212\u221e &lt; x &lt; \u221e. It can be shown that E(X) = \u00b5 and V (X) = \u03c3 2. Thus, the normal distribution is characterized by a mean \u00b5 and a standard deviation \u03c3.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.1.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Discrete Random Variable<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A discrete random variable is one whose set of assumed values is countable (arises from counting). Discrete random variable whose values are\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">countable is called a discrete random variable. An example of this is the number of cars in a parking lot at any particular time.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">4.2.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">Continuous Random Variable<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A continuous random variable is one whose set of assumed values is uncountable (arises from measurement.).Continuous random variable that can assume any value in one or more intervals is called a continuous random variable. An example of this is the time taken by a person to travel by car from New York City to Boston.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">5.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0<\/span><strong style=\"text-align: initial;font-size: 1em\">BINOMIAL DISTRIBUTION<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">In probability theory and <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistics\">statistics, <\/a><span style=\"text-align: initial;font-size: 1em\">the <\/span><strong style=\"text-align: initial;font-size: 1em\">binomial distribution<\/strong><span style=\"text-align: initial;font-size: 1em\"> is the <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete<\/a> <a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">probability distribution <\/a><span style=\"text-align: initial;font-size: 1em\">of the number of successes in a sequence of <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em> <a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistical_independence\">independent<\/a><span style=\"text-align: initial;font-size: 1em\"> yes\/no experiments, each of which yields success with <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Probability\">probability <\/a><em style=\"text-align: initial;font-size: 1em\">p<\/em><span style=\"text-align: initial;font-size: 1em\">. Such a success\/failure experiment is also called a Bernoulli experiment or <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Bernoulli_trial\">Bernoulli trial. <\/a><span style=\"text-align: initial;font-size: 1em\">In fact, when <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em><span style=\"text-align: initial;font-size: 1em\"> = 1, the binomial distribution <\/span><em style=\"text-align: initial;font-size: 1em\">is<\/em><span style=\"text-align: initial;font-size: 1em\"> a Bernoulli distribution. The binomial distribution is the basis for the popular <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Binomial_test\">binomial test <\/a><span style=\"text-align: initial;font-size: 1em\">of <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Statistical_significance\">statistical significance.<\/a><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE &#8211;<\/strong><\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">An elementary example is this: roll a die ten times and count the number of 1s a outcome. Then this random number follows a binomial distribution with n = 10 and p =1\/6.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">For example, assume 5% of the population is green-eyed. You pick 500 people randomly. The number of green-eyed people you pick is a <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Random_variable\">random variable <\/a><em style=\"text-align: initial;font-size: 1em\">X<\/em><span style=\"text-align: initial;font-size: 1em\"> which follows a binomial distribution with <\/span><em style=\"text-align: initial;font-size: 1em\">n<\/em><span style=\"text-align: initial;font-size: 1em\"> = 500 and <\/span><em style=\"text-align: initial;font-size: 1em\">p<\/em><span style=\"text-align: initial;font-size: 1em\"> = 0.05.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">6.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">CONDITIONAL PROBABILITY<\/strong><\/p>\n<\/div>\n<div>\n<p style=\"text-align: justify\">The conditional probability of two events A and B is P (A|B) =<em>P<\/em>(<em> A\u00a0\u00a0 and P<\/em>(<em>B<\/em>)\u00a0<em>B<\/em>)<\/p>\n<p style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">where P (A and B) means the probability of the outcomes that events A and B have in common.<\/span><\/p>\n<\/div>\n<div>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>(i)\u00a0\u00a0<\/strong><strong>EXAMPLE \u2013<\/strong><\/p>\n<p style=\"text-align: justify\">When a die is rolled once, find the probability of getting a 4 given that an even number occurred in an earlier throw.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">P (4 and an even number) = 1\/6<\/p>\n<p style=\"text-align: justify\">.i.e. P (A and B) =1\/6.<\/p>\n<p style=\"text-align: justify\">P (even number) =3\/6 =1\/2.<\/p>\n<p style=\"text-align: justify\"><a href=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/chapter\/probability-distribution\/untitled-152\/\" rel=\"attachment wp-att-330\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-330\" src=\"http:\/\/hsp16.epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-94.png\" alt=\"\" width=\"272\" height=\"71\" srcset=\"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-94.png 272w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-94-65x17.png 65w, https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-content\/uploads\/sites\/292\/2019\/08\/Untitled-94-225x59.png 225w\" sizes=\"auto, (max-width: 272px) 100vw, 272px\" \/><\/a><strong style=\"text-align: initial;font-size: 1em\">\u00a0 \u00a0(ii)\u00a0\u00a0\u00a0\u00a0\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">EXAMPLE &#8211;<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">A bag contains 3 orange, 3 yellow and 2 white marbles. Three marbles are selected without replacement. Find the probability of selecting two yellow and a white marble.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P( 1st Y) =3\/8, P( 2nd Y) = 2\/7 and P( W)= 2\/6<\/span><\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P(Y and Y and W) =P(Y) x P(Y) x P (W) = 3\/8 x 2\/7 x 2\/6 = 1 \/ 28<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(iii)\u00a0\u00a0\u00a0\u00a0<\/strong><span style=\"text-align: initial;font-size: 1em\">In a class, there are 8 girls and 6 boys. If three students are selected at random for debating, find the probability that all girls.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (G) =8\/14 and P (B) =6\/14. P (1st G) =8\/14, P (2nd G) 7\/13 and P (3rdG) = 6\/12. P (three girls) 8\/14 x 7\/13 x 6\/12= 2\/13<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(iv)<\/strong><span style=\"text-align: initial;font-size: 1em\">In how many ways can 3 drama officials be selected from 8 members?<\/span><\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">8<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">3 <\/strong><span style=\"text-align: initial;font-size: 1em\">= 56 ways.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(v)\u00a0\u00a0<\/strong><span style=\"text-align: initial;font-size: 1em\">A box has 12 bulbs, of which 3 are defective. If 4 bulbs are sold, find the probability that exactly one will be defective.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (defective bulb) = <\/span><strong style=\"text-align: initial;font-size: 1em\">3<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">1<\/strong><span style=\"text-align: initial;font-size: 1em\"> and P (non-defective bulbs) = <\/span><strong style=\"text-align: initial;font-size: 1em\">9<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">3<\/strong><\/p>\n<p><strong>3<\/strong><strong>C<\/strong><strong>1 <\/strong>x<strong>9<\/strong><strong>C<\/strong><strong>3 <\/strong>=\u00a03!<em>x\u00a09!= 252<\/em><\/p>\n<p>(3 -1)!1!\u00a0(9 &#8211; 3)!3!<\/p>\n<p><span style=\"text-align: initial;font-size: 1em\">P (4 bulbs from 12) = <\/span><strong style=\"text-align: initial;font-size: 1em\">12<\/strong><strong style=\"text-align: initial;font-size: 1em\">C<\/strong><strong style=\"text-align: initial;font-size: 1em\">4<\/strong><span style=\"text-align: initial;font-size: 1em\"> = 495.<\/span><\/p>\n<p><span style=\"text-align: initial;font-size: 1em\">P (1 defective bulb and 3 okay bulbs) = 295\/495=0.509.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">7.<\/strong><span style=\"text-align: initial;font-size: 1em\">\u00a0\u00a0\u00a0 <\/span><strong style=\"text-align: initial;font-size: 1em\">POISSON DISTRIBUTION<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Poisson distribution: is a <\/span><a style=\"text-align: initial;font-size: 1em\" href=\"http:\/\/en.wikipedia.org\/wiki\/Discrete_probability_distribution\">discrete probability distribution <\/a><span style=\"text-align: initial;font-size: 1em\">that expresses the probability of a number of events occurring in a fixed period of time if these events occur with a known average rate, and are independent of the time since the last event. The Poisson distribution arises in many situations. It is safe to say that it is one of the three most important discrete probability distributions (the other two being the uniform and the binomial distributions). The Poisson distribution can be viewed as arising from the binomial distribution or from the exponential density.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">If the parameters n &amp; p of a binomial distribution are known then we can find the distribution. But when n is large and p is very small the application of binomial distribution is very difficult. Let x be any discrete random variable which can take values 0,1,2,3\u2026.. such that the probability distribution function of x<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P(x)=e -\u03bb \u03bbx\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">x!<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">where \u03bb is a positive constant, np = \u03bb . This distribution is called the poisson distribution.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">\u00a0Number of printing mistakes on each page of a book published by a good publisher<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of telephone calls arriving at a telephone switch board per minute<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">The Poisson distribution is a common distribution used to model \u201ccount\u201d data:<\/span><\/p>\n<ul>\n<li style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of telephone calls received per hour<\/span><\/li>\n<li style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Number of claims received per day by an insurance company<\/span><\/li>\n<li style=\"text-align: justify\"><span style=\"font-size: 1em;text-align: initial\">Number of accidents per month at an intersection<\/span><\/li>\n<\/ul>\n<\/div>\n<div>\n<p style=\"text-align: justify\"><strong>8.\u00a0\u00a0<\/strong><strong>OBJECTIVES OF PROBABILITY DISTRIBUTION <\/strong>The core objectives of tabulation are mentioned below:<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">(a)To compute and interpret the expected value, variance, and standard deviation for a discrete random variable and work with probabilities involving a binomial probability distribution.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">(b)To work out the probabilities involving a Poisson probability distribution,<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">(c)Understand the concepts of a random variable and a probability distribution.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">(d) To decide the binomial distribution problems to be approximated by the Poisson distribution , to use the Poisson distribution in analyzing statistical<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">(e)To use the hyper geometric distribution and know how to work such problems.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>9. RULES OF PROBABILITY<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>(a)\u00a0\u00a0 <\/strong><strong>ADDITION RULES I. Rule &#8211; 1:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">When two events A and B are mutually exclusive, then P (A or B) =P (A) +P (B)<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>Example &#8211;<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">When a is tossed, find the probability of getting a 3 or 5.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">Solution: P (3) =1\/6 and P (5) =1\/6.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">Therefore P (3 or 5) = P (3) + P (5) = 1\/6+1\/6 =2\/6=1\/3.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>II. Rule \u2013 2:<\/strong><\/p>\n<p style=\"text-align: justify\">If A and B are two events that are NOT mutually exclusive, then P (A or B) = P (A)<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">+\u00a0\u00a0 P (B) \u2013 P (A and B), where A and B means the number of outcomes that event A and B have in common.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>Example \u2013<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">When a card is drawn from a pack of 52 cards, find the probability that the card is a 10 or a heart.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong>Solution:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">P (10) = 4\/52 and P (heart) =13\/52<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">P (10 that is Heart) = 1\/52<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\">P (A or B) = P (A) +P (B) \u2013 P (A and B) = 4\/52 _ 13\/52 \u2013 1\/52 = 16\/52.<\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">(b) MULTIPLICATION RULES<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">I.\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">Rule \u2013 1: <\/strong><span style=\"text-align: initial;font-size: 1em\">For two independent events A and B, then P (A and B) = P (A) x P (B).<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Determine the probability of obtaining a 5 on a die and a tail on a coin in one throw.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution: <\/strong><span style=\"text-align: initial;font-size: 1em\">P (5) =1\/6 and P (T) =1\/2.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P (5 and T) = P (5) x P (T) = 1\/6 x \u00bd= 1\/12.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">II.\u00a0<\/strong><strong style=\"text-align: initial;font-size: 1em\">Rule \u2013 2:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">When to events are dependent, the probability of both events occurring is P(A and\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">B)=P(A) x P(B|A), where P(B|A) is the probability that event B occurs given that\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">event A has already occurred.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Example \u2013<\/strong><span style=\"text-align: initial;font-size: 1em\">Find\u00a0 the\u00a0 probability\u00a0 of\u00a0 obtaining\u00a0 two\u00a0 Aces\u00a0 from\u00a0 a\u00a0 pack\u00a0 of\u00a0 52\u00a0 cards\u00a0 without\u00a0<\/span><span style=\"text-align: initial;font-size: 1em\">replacement.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">Solution:<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">P( Ace) =2\/52 and P( second Ace if NO replacement) = 3\/51<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Therefore P (Ace and Ace) = P(Ace) x P( Second Ace) = 4\/52 x 3\/51 = 1\/221<\/span><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><strong style=\"text-align: initial;font-size: 1em\">10. MERITS OF PROBABILITY DISTRIBUTION<\/strong><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify\"><span style=\"text-align: initial;font-size: 1em\">Merits of probability distribution and benefits of theoretical or probability distribution<\/span><\/p>\n<ul>\n<li><span style=\"text-align: initial;font-size: 1em\">Where the calculation of observed distribution is not possible.<\/span><\/li>\n<li>Sometime observed base distribution&#8217;s calculation is not possible due to impossibility at that place we can calculate probability distribution.<\/li>\n<li>Helpful in forecasting \u2013 Probability distribution isvery helpful for forecasting and on this basis we can estimate our future and make good plans for our business.<\/li>\n<li>Helpful in Comparison \u2013 It can compare it with observed or real distribution and evaluate our efficiency of work.<\/li>\n<\/ul>\n<\/div>\n<ol start=\"11\">\n<li><strong>LIMITATIONS OF PROBABILITY DISTRIBUTION<\/strong><\/li>\n<\/ol>\n<ul>\n<li style=\"text-align: justify\">Probability distribution cannot be correlated<\/li>\n<li style=\"text-align: justify\">Probability distribution cannot be viewed in chart form or in any statistical view<\/li>\n<li style=\"text-align: justify\">The data cannot be extract data from probability distribution or it cannot include in the reports<\/li>\n<li style=\"text-align: justify\">It is excluded from sensitivity analyses or charts.<\/li>\n<li style=\"text-align: justify\">Probability distribution doesn\u2019t support the Latin Hypercube sampling<\/li>\n<\/ul>\n<ol style=\"text-align: justify\" start=\"12\">\n<li><strong>CONCLUSION<\/strong><\/li>\n<\/ol>\n<p style=\"text-align: justify\">To summaries, the probability has become one of the basic tools of statistics. Sometimes statistical analysis becomes paralyzed without the theorem of probability. Probability of a given event is defined as the expected frequency of occurrence of the event among events of a like sort. According to basic economic theory, people wish to maximize their expected utility. In order to do so they should integrate the likelihood (i.e. probability) and the possible outcomes (good or bad). This means that people maximize their utility based on their perceived importance of probabilities and outcomes.<\/p>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<td><span style=\"font-size: 16px\">you can view video on Probability Distribution <\/span><\/td>\n<td><a style=\"font-size: 16px\" href=\"https:\/\/youtu.be\/lmu7WJ0AhS8\" target=\"_blank\" rel=\"noopener\"><span style=\"color: #333333\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-120\" src=\"http:\/\/epgpbooks.inflibnet.ac.in\/wp-content\/uploads\/2018\/11\/download.png\" alt=\"\" width=\"36\" height=\"36\" \/><\/span><\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong><em>Web links<\/em><\/strong><\/p>\n<ul>\n<li style=\"text-align: justify\">https:\/\/www.merriam-webster.com\/dictionary\/probability<\/li>\n<li style=\"text-align: justify\">http:\/\/whatis.techtarget.com\/definition\/probability<\/li>\n<li style=\"text-align: justify\">http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda361.htm<\/li>\n<li style=\"text-align: justify\">http:\/\/study.com\/academy\/lesson\/probability-distribution-definition-formula-example.html<\/li>\n<li style=\"text-align: justify\">https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php<\/li>\n<li style=\"text-align: justify\">https:\/\/onlinecourses.science.psu.edu\/stat200\/node\/34<\/li>\n<li style=\"text-align: justify\">https:\/\/www.thoughtco.com\/probability-distribution-3126569<\/li>\n<li style=\"text-align: justify\">https:\/\/people.richland.edu\/james\/lecture\/m170\/ch06-prb.html<\/li>\n<li style=\"text-align: justify\">https:\/\/www.utdallas.edu\/~scniu\/OPRE-6301\/documents\/Important_Probability_Distributions.pdf<\/li>\n<li style=\"text-align: justify\">http:\/\/www.ce.memphis.edu\/7012\/pdf%20files\/Discrete_notes.pdf<\/li>\n<li style=\"text-align: justify\">https:\/\/cran.r-project.org\/web\/packages\/IPSUR\/vignettes\/IPSUR.pdf<\/li>\n<li style=\"text-align: justify\">http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda3661.htm<\/li>\n<li style=\"text-align: justify\"><a href=\"https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php\">https:\/\/www.intmath.com\/counting-probability\/11-probability-distributions-concepts.php<\/a><\/li>\n<li style=\"text-align: justify\">http:\/\/study.com\/academy\/lesson\/probability-distribution-definition-formula-example.html http:\/\/www.itl.nist.gov\/div898\/handbook\/eda\/section3\/eda36.htm<\/li>\n<li style=\"text-align: justify\">https:\/\/www.slideshare.net\/bijayabnanda\/ls-bs-9probability-concept-and-probability-distribution<\/li>\n<li style=\"text-align: justify\">https:\/\/www.wyzant.com\/resources\/lessons\/math\/statistics_and_probability\/probability_dis tributions<\/li>\n<\/ul>\n","protected":false},"author":8,"menu_order":39,"template":"","meta":{"pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":["dr-smt-v-vimala"],"pb_section_license":""},"chapter-type":[],"contributor":[71],"license":[],"class_list":["post-318","chapter","type-chapter","status-publish","hentry","contributor-dr-smt-v-vimala"],"part":3,"_links":{"self":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapters\/318","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/wp\/v2\/users\/8"}],"version-history":[{"count":4,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapters\/318\/revisions"}],"predecessor-version":[{"id":334,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapters\/318\/revisions\/334"}],"part":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/parts\/3"}],"metadata":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapters\/318\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/wp\/v2\/media?parent=318"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/pressbooks\/v2\/chapter-type?post=318"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/wp\/v2\/contributor?post=318"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/ebooks.inflibnet.ac.in\/hsp16\/wp-json\/wp\/v2\/license?post=318"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}